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Multiply Strings
Approach
Multiply two numeric strings without converting to built-in big integers.
Schoolbook multiplication: digit i of num1 and digit j of num2 contribute to position i + j in the result (from the right).
Store partial sums in an array of length len(num1) + len(num2), then build the answer string skipping leading zeros.
Time Complexity: O(m × n)
Space Complexity: O(m + n)
Code
class Solution:
def multiply(self, num1: str, num2: str) -> str:
if num1 == "0" or num2 == "0":
return "0"
m, n = len(num1), len(num2)
pos = [0] * (m + n)
for i in range(m - 1, -1, -1):
for j in range(n - 1, -1, -1):
mul = int(num1[i]) * int(num2[j])
p1, p2 = i + j, i + j + 1
total = mul + pos[p2]
pos[p1] += total // 10
pos[p2] = total % 10
start = 0
while start < len(pos) - 1 and pos[start] == 0:
start += 1
return "".join(str(d) for d in pos[start:])